حالات الكيوبت بـ numpy

import numpy as np

ket0 = np.array([1, 0], dtype=complex)
ket1 = np.array([0, 1], dtype=complex)
plus = (ket0 + ket1) / np.sqrt(2)
minus = (ket0 - ket1) / np.sqrt(2)

for name, state in [("|0>", ket0), ("|1>", ket1), ("|+>", plus), ("|->", minus)]:
    probs = np.abs(state) ** 2
    print(f"{name}: الطول = {np.linalg.norm(state):.3f} | P(0) = {probs[0]:.3f} | P(1) = {probs[1]:.3f}")

import numpy as np

ket0 = np.array([1, 0], dtype=complex)
plus = np.array([1, 1], dtype=complex) / np.sqrt(2)

state = np.kron(plus, ket0)
labels = ["00", "01", "10", "11"]

print("الحالة:", np.round(state.real, 4))
for label, amp in zip(labels, state):
    print(f"P({label}) = {abs(amp) ** 2:.3f}")
print("المجموع:", round(float(np.sum(np.abs(state) ** 2)), 6))

import numpy as np
import matplotlib.pyplot as plt

rng = np.random.default_rng(42)
plus = np.array([1, 1]) / np.sqrt(2)
probs = np.abs(plus) ** 2

shots = 1000
outcomes = rng.choice([0, 1], size=shots, p=probs)
counts = [int(np.sum(outcomes == 0)), int(np.sum(outcomes == 1))]
print("النتائج:", {"|0>": counts[0], "|1>": counts[1]})

plt.figure(figsize=(4.5, 3.2), dpi=100)
plt.bar(["|0>", "|1>"], counts, color=["#0D5C43", "#22C55E"])
plt.ylabel("count")
plt.title("1000 shots on |+>")
plt.show()